1.2.2 Number of edges

Remark 1.2.6   We can construct any graph together with its incidence matrix from scratch, adding edge by edge. That is, start with a graph with % latex2html id marker 4881
$ \alpha$ vertices % latex2html id marker 4883
$ A_1,\dots,A_{\alpha}$ and no edges at all. Note that the incidence matrix of this graph is the % latex2html id marker 4885
$ \alpha\times\alpha$ matrix filled with zeros.

Now adding an edge we should distinguish between the loops and the edges connecting different vertices. Adding a loop to the vertex $ A_i$ we have to replace $ m_{ii}$ by $ m_{ii}+1$ . Adding an edge that connects $ A_i$ with $ A_j$ , where $ i\ne j$ , we have to replace both $ m_{ij}$ and $ m_{ji}$ by $ m_{ij}+1$ and $ m_{ji}+1$ , correspondingly. Note that by induction it follows that $ m_{ij}=m_{ji}$ for all $ i,j$ .

These remark makes the following statement obvious:

Lemma 1.2.7   Let a matrix

% latex2html id marker 4916
$\displaystyle \left (
\begin{array}{ccc}
m_{11}&\d...
...\dots&\dots&\dots\\
m_{\alpha1}&\dots&m_{\alpha\alpha}\\
\end{array}\right )
$

be an incidence matrix of some graph. Then the total number of edges of this graph is

% latex2html id marker 4918
$\displaystyle \sum_{1\le i\le j\le\alpha}m_{ij}.
$

Exercise 1.2.8   If you feel it necessary, construct the rigorous inductive proof of Lemma [*].

Exercise 1.2.9   List all the possible incidence matrices of connected graphs with 1,2 and 3 edges.

Control question 1.7   Give the number of matrices, you have got in Exercise [*].

Control question 1.8   Would Exercise [*] remain reasonable if we omit the word "connected"?

You may use the answer form at the end of this lecture to answer these questions.